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# How to Loop Over a String in Reverse in Python [All Method]️

The step-by-step guide on this page will show you How to Loop Over a String in Reverse in Python. By the end of this guide, you will know how to handle these types of problems.
Question: What is the best way to approach this problem? Answer: Check out this blog code to learn how to fix errors How to Loop Over a String in Reverse in Python. Question: What are the reasons for this code mistake and how can it be fixed? Answer: You can find a solution by following the advice in this blog.

We’ve all had to iterate backwards over a string at some point, whether it’s in a project itself or a coding interview.

Suppose we’re iterating backwards over the string `s`, which we define as `hello`.

``````s = 'hello'
``````

Let’s see how we can do this.

## Using `range()`

The definition of `range()` looks like this:

``````range(?start, stop, ?step)
``````

When we only have one parameter, that defines our `stop` value (our start value defaults to `0`).

``````# Iterates from [0, len(s))
for i in range(len(s)):
print(s[i]) # 'h', 'e', 'l', 'l', 'o'
``````

When we have two parameters, they defines our `start` and `stop` values.

``````# Iterates from [1, len(s))
for i in range(1, len(s)):
print(s[i]) # 'e', 'l', 'l', 'o'
``````

When we use all three parameters, we can specify our `step` interval, which can be `-1` to define a backwards iteration.

``````# Iterates [len(s)-1, -1) backwards
for i in range(len(s)-1, -1, -1):
print(s[i]) # 'o', 'l', 'l', 'e', 'h'
``````

## Using `string.reverse()`

We can reverse a string in-place using the `string.reverse()` method.

``````s.reverse() # None
for char in s:
print(char) # 'o', 'l', 'l', 'e', 'h'
``````

## Using `[::-1]`

Every iterable object in Python has this slicing feature.

Similar to the `range()` definition, the slicing feature is defined as follows:

``````[start:stop:step]
``````

We can create a reversed copy of a string using this slicing technique, which looks something like this:

``````for char in s[::-1]:
print(char) # 'o', 'l', 'l', 'e', 'h'
``````

We are copying the entire string (as defined by the empty indexes for `start` and `stop`) backwards (as defined by the `-1` step interval).

However, this method requires much more memory compared to any of the other options. It creates a shallow copy of the object at hand. This means that we’re simply copying the references from the original list.

Any change made to the original list will be reflected in this copied list as well.

## Using `reversed()`

The last option is to use `reversed()`, which creates a reverse iterator. The string is never actually reversed, and there is no actual copy made.

We just cycle through the string in reverse order.

``````for char in reversed(s):
print(char) # 'o', 'l', 'l', 'e', 'h'
``````

Revise the code and make it more robust with proper test case and check an error there before implementing into a production environment.
Now you can solve your code error in less than a minute.